Algebra review
parentheses, exponents, multiplication, division, addition, subtraction
A common mnemonic device people use to memorize order of operations is
PEMDAS
or Please Excuse My Dear Aunt Sally.
You will also encounter the percentage change in a variable, which is calculated as: \(\frac{x_{t+1}-x_t}{x_t}\), where the subscript \(t\) indicates the first observation and the subscript t + 1 indicates the second observation.
\[ \frac{Numerator}{Denominator} \]
Example:
\[ \delta+\delta^2+4\delta-6\delta^2+18\delta^3\]
In this case we combine all the terms that have the same exponent, which gives us \[ 18\delta^3-5\delta^2+5\delta\]
Quadratic polynomials are composed of a constant and a variable that is both squared and raised to the power of one: \(x^2-2x+3\), or \(7-12x+6x^2\). Quadratic polynomials can be factored into the product of two terms: \((x \pm ?) \times (x \pm ?)\) where you need to determine whether the sign is \(+\) or \(-\), and then replace the question marks with the proper values.
Consider the fraction \(\frac{x^2-1}{x-1}\)
We can factor the numerator \(x^2-1=(x+1)(x-1)\). We can thus rewrite the fraction as follows:
\[ \frac{x^2-1}{x-1}= \frac{(x+1)(x-1)}{x-1} \]
The term \(x-1\) is in both the numerator and the denominator and thus (as long as \(x\neq 1\)) cancels out, leaving \(x+1\) for \(x \neq 1\)
\[ (\delta + \gamma)^2 \]
\[=(\delta + \gamma)(\delta + \gamma)\]
\[ =\delta^2 + 2\delta\gamma + \gamma^2 \]
F: Multiply the first terms: \((\underline{2\pi}+7) (\underline{4}+3\pi)=2 \pi \times 4=8 \pi\)
O: Multiply the outer terms: \((\underline{2\pi}+7) (4+\underline{3\pi})=2 \pi \times 3 \pi=6 \pi^2\)
I: Multiply the inner terms: \((2\pi+\underline{7}) (\underline{4}+3\pi)=4 \times 7=28\)
L: Multiply the last terms: \((2\pi+\underline{7}) (4+\underline{3\pi})=7 \times 3 \pi=21 \pi\)
Add terms to get: \(8\pi+6\pi^2+28+21\pi\)
Finally, group like terms to get: \(6\pi^2+29\pi+28\)
To test yourself, factor the final expression and show it yields the simplified expression with which we started. This is one way to check your work for any mistakes.
Example:
\[ (x-3)^2=4 \]
\[ x-3=\pm 2 \]
\[ x=5 \text{ or } x=1 \]
Note that this quadratic equation will have two solutions in the real numbers, or zero, but not one. In other words, the cardinality of the solution set for a quadratic equation will be zero or two.
Example with no solutions in the real numbers: \(x^2+1=0\)
Another example: \[ x^2+8x+6=0 \]
The general form of a quadratic equation:
\[
ax^2+bx+c=0
\]
The general solutions to this equation: \[ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \]
Example:
Solve for \(y\):
\[
-4y>2x+12
\]
\[ y<-\frac{x}{2}-3 \]
Exercise:
\[ 1.4x^2+3.7x+1.1=0 \]
Answer:
\[ a=1.4, b=3.7, c=1.1 \]
\[ x=\frac{-3.7 \pm \sqrt{3.7^2-4 \times 1.4 \times 1.1}}{2.8} \]
Using a calculator to solve, we find that \(x=-.341 \text{ or } x=-2.301\)
Complete the following equations
\(\prod_{m=6}^9 x_m = \ldots\)
\(\sqrt[3]{27} = \ldots\)
Simplify this expression as much as possible: \(\frac{2x^2 + 20x + 50}{2x^2 - 50}\)
FOIL: \((2x - 3)(5x + 7)\)
Complete the square and solve for y: \(\frac{1}{3}y^2 + \frac{2}{3}y - 16 = 0\)
Solve using the quadratic formula: \(2x^2 + 5x - 7 = 0\)
Solve: \(-\delta > \frac{\delta+4}{7}\)
A firm faces the marginal revenue schedule \(MR = 80 - 2q\) and the marginal cost schedule \(MC = 15 + 0.5q\), where \(q\) is the quantity produced. You know that a firm maximizes profit when \(MC = MR\). What will the profit-maximizing output be?
Derive the quadratic formula by completing the square for the equation \(ax^2 + bx + c = 0\).
Any Questions?